Answer:
- 40 packages from Fred Motors
- 20 packages from Admiral Motors
- 40 packages from Chrysalis
Step-by-step explanation:
I would formulate the problem like this. Let f, a, c represent the numbers of packages bought from Fred Motors, Admiral Motors, and Chrysalis, respectively. Then the function to minimize (in thousands) is …
objective = 500f +400a +300c
The constraints on the numbers of cars purchased are …
5f +5a +10c >= 700
5f +10a +5c >= 600
10f +5a +5c >= 700
Along with the usual f >=0, a>=0, c>=0. Of course, we want all these variables to be integers.
Any number of solvers are available in the Internet for systems like this. Shown in the attachments are the input and output of one of them.
The optimal purchase appears to be …
- 40 packages from Fred Motors
- 20 packages from Admiral Motors
- 40 packages from Chrysalis
The total cost of these is $40 million.
The functions that the left endpoint lead to an under approximation and right endpoints lead to and over approximation is the positive and increasing function.
<h3>How to illustrate the function?</h3>
It should be noted that function simply means the illustration that shows the relationship between the variables.
In this case, the functions that the left endpoint lead to an under approximation and right endpoints lead to and over approximation is the positive and increasing function.
Learn more about functions on:
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(m + 3)^2 -16
=(m + 3)^2 - 4^2
=((m+3) + 4)*((m+3) - 4)
=(m+7)(m-1)
Here are the formulas i used:
so first i made 16 to 4^2, then i use (a^2 -b^2)= (a+b)(a-b) . In this case a would be (m+3) and b is 4.
Remember you can do anything to an equatino as long as you do it to both sides
add 6n to both sides
6n-5n=6n-6n-4
1n=0n-4
n=-4
Answer:
all books to new books- 14:5
used books to new books- 5:9
Step-by-step explanation:
