Question

At LaGuardia Airport for a certain nightly flight, the probability that it will rain is 0.14 and the probability that the flight will be delayed is 0.16. The probability that it will not rain and the flight will leave on time is 0.79. What is the probability that it is not raining if the flight has been delayed?a. P(delayed | rain) = 0.08.
b. P(delayed | rain) = 0.083.
c. P(rain | delayed) = 0.06.
d. P(rain | delayed) = 0.056.

Answer 1

Answer:

The appropriate answer is "0.437".

Step-by-step explanation:

Given:

P(rain) = 0.14

then,

P(no-rain) = 1-P(rain)

                 = 1-0.14

                 = 0.86

P(delay) = 0.16

P(rain and on time) = 0.79

then,

By using the conditional probability, we get

⇒ $P(A|B)=\frac{P(A \cap B)}{P(B)}$

or,

⇒ $P(no \ rain|delay) = \frac{P(no \ rain \cap delay)}{P(delay)}$

By substituting the values, we get

⇒                             $=\frac{0.07}{0.16}$

⇒                             $=0.437$