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jarptica [38.1K]
3 years ago
9

Find the LCM of the set of numbers 5 10 15 DUE TODAY

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

C

Step-by-step explanation:

The LCM of 5, 10, 15

Is the result of multiplying all prime factors the greatest number of times they occur in either number. The LCM of 5, 10, 15 is 2*3*5=30

mel-nik [20]3 years ago
6 0

Hello.

The LCM is the smallest number that they all have in common when adding it by itself.

The multiples of 5: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50...

The multiples of 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100...

The multiples of 15: 15, 30, 45, 60, 75, 90, 105, 120, 135, 150...

The Least Common Multiple is 30.

The answer is C. 30

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irakobra [83]

Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.

----------------------

  • According to Benford's law, the probability of a number starting with digit is d is:

P(d) = \log{(d + 1}} - \log{d}

  • A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
  • Thus, d can only assume integer digits.
  • In the graph, the solution is d < 5.
  • The integer options for values of d are 1 and 4.
  • For the other options that are less than 5, they are not integers, so d cannot assume those values.

A similar problem is given at brainly.com/question/16764162

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Solve for n.<br> 2n - 3<br> 5<br> =<br> = 5<br> Enter your answer in the box.<br> n =
Zina [86]

Answer:

2n - 35 = 5 \\ 2n = 5 + 35 \\ 2n = 40 \\ n = 40 \div 2 \\ n = 20

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what is an equation of the line that passes through the point (5,5) and is perpendicular to the line whose equation is y=5/9x-4
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2. A two-stage rocket is in development. The required probability is for the overall rocket to be a minimum of 97% reliable for
ikadub [295]

Answer: The minimum reliability for the second stage be 0.979.

Step-by-step explanation:

Since we have given that

Probability for the overall rocket reliable for a successful mission = 97%

Probability for the first stage = 99%

We need to find the minimum reliability for the second stage :

So, it becomes:

P(overall reliability) = P(first stage ) × P(second stage)

0.97=0.99\times x\\\\\dfrac{0.97}{0.99}=x\\\\0.979=x

Hence, the minimum reliability for the second stage be 0.979.

4 0
3 years ago
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