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alexira [117]
3 years ago
7

1 x 10^12 = 9 x 10^8 (8/d^2) solve for d

Mathematics
1 answer:
Maslowich3 years ago
6 0

Answer: Go here https://quickmath.com/webMathematica3/quickmath/equations/solve/basic.jsp

Step-by-step explanation:

It will show you how

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What is 9/10 + 7/15
Yakvenalex [24]

\huge\text{Hey there!}

\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}

\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}

\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}

\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}

\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}

\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}

\mathsf{= \dfrac{27+14}{30}}

\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}

\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}

\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
3 years ago
Read 2 more answers
francine has a square mosaic that is made from small glass squares. if there are 196 small squares in the mosiac, how many are a
Kruka [31]
There would be 56 becasue you calculate the square root of 196 which is 14 and multiply by 4 
5 0
4 years ago
Three numbers have absolute values of 2,4 and 9. The product of all the numbers is positive.
Margaret [11]
The absolute value of a number is how far away it is from 0 on a number line.
Example) 2 is two numbers away from 0, but neg. 2 (-2) is also two numbers away from 0

So basically. A positive number has the absolute value of itself. (2= a value of 2) and negative numbers have the absolute value of the positive form of that number. (-9= a value of 9)

Numbers that have the absolute value of 2: 2 and -2
Numbers that have the absolute value of 4: 4 and -4
Numbers that have the absolute value of 9: 9 and -9

You are looking to add your numbers together to make a positive.

So the answer is the positive answers to the absolute values: 2,4,9

2+4+9=15

15 is a positive number.
8 0
3 years ago
Write the standard form of the simplest polynomial with the roots 2, 3, and -3
koban [17]

\text{If}\ x_1,\ x_2\ \text{and}\ x_3\ \text{are roots of a polynomial, then we can write that polynomial}\\\text{in form}\ (x-x_1)(x-x_2)(x-x_3).\\\\\text{We have\ the\ roots:}\ 2,\ 3\ \text{and}\ -3.\\\\w(x)=(x-2)(x-3)(x-(-3))=(x-2)\underbrace{(x-3)(x+3)}_{use\ a^2-b^2=(a-b)(a+b)}\\\\=(x-2)(x^2-9^2)=(x-2)(x^2-9)=(x)(x^2)+(x)(-9)+(-2)(x^2)+(-2)(-9)\\\\=x^3-9x-2x^2+18=\boxed{x^3-2x^2-9x+18}

5 0
4 years ago
Y" - 4y = (x2 - 3) sin 2x
Zolol [24]
y''-4y=0

has characteristic equation

r^2-4=0

which has roots at r=\pm2, giving the characteristic solution

y_c=C_1e^{2x}+C_2e^{-2x}

For the nonhomogeneous part of the ODE, let y_p=(a_2x^2+a_1x+a_0)\sin2x+(b_2x^2+b_1x+b_0)\cos2x. Then

{y_p}''=(-4b_2x^2+(8a_2-b_1)x+4a_1-4b_0+2b_2)\cos2x+(-4a_2x^2+(-4a_1-8b_2)x-4a_0+2a_2-4b_1)\sin2x

Substituting into the ODE gives

(-8b_2x^2+(8a_2-b_1)x+4a_1-8b_0+2b_2)\cos2x+(-8a_2x^2+(-8a_1-8b_2)x-8a_0+2a_2-4b_1)\sin2x=(x^2-3)\sin2x

It follows that

\begin{cases}-8b_2=0\\8a_2-8b_1=0\\4a_1-8b_0+2b_2=0\\-8a_2=1\\-8a_1-8b_2=0\\-8a_0+2a_2-4b_1=-3\end{cases}\implies\begin{cases}a_2=-\dfrac18\\\\a_1=0\\\\a_0=\dfrac{13}{32}\\\\b_2=0\\\\b_1=-\dfrac18\\\\b_0=0\end{cases}

which yields the particular solution

y_p=-\dfrac18x^2\sin2x+\dfrac{13}{32}\sin2x-\dfrac18x\cos2x

So the general solution is

y=y_c+y_p
y=C_1e^{2x}+C_2e^{-2x}-\dfrac18x^2\sin2x+\dfrac{13}{32}\sin2x-\dfrac18x\cos2x
4 0
3 years ago
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