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Lena [83]
3 years ago
8

PLZ HELP ME WITH THIS IT IS SO CONFUSING ON 10 MINUTES LET PLZZZ ILL GVE BRAINLIEST

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Answer:

f =  3x^2+ 1  / x

Step-by-step explanation:

Let's solve for f.

fx=3x2+1

Step 1: Divide both sides by x.

fx  / x  =  3x^2+1  / x

f=  3x2+1  / x

Serggg [28]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = 3x² + 1

To obtain f(- 1) substitute x = - 1 into f(x) , that is

(8)

f(- 1) = 3(- 1)² + 1 = 3(1) + 1 = 3 + 1 = 4

(9)

Similarly

f(0) = 3(0)² + 1 = 3(0) + 1 = 0 + 1 = 1

(10)

Given

f(x) = 3x² + 1 and f(x) = 49, then equate right sides

3x² + 1 = 49 ( subtract 1 from both sides )

3x² = 48 ( divide both sides by 3 )

x² = 16 ( take the square root of both sides )

x = ± \sqrt{16} = ± 4

That is x = - 4 or x = 4

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WHOEVER GETS RIGHT GETS BRAINLIEST!!
ozzi

Answer:

Answer B:  min. value at -6

Step-by-step explanation:

Complete the square of f(x) = x^2 - 2x - 5.

Note:  Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term:  it is 2.

Take half of that and square your result:  (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x    + 1   - 1  - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or    f(x) = (x - 1)^2 - 6

Compare this to the standard form

                                        f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B:  min. value at -6.

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Step-by-step explanation:

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there really isnt anything to explain

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