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3 years ago

What conclusion can be made for c and e?

Mathematics

1 answer:

34kurt3 years ago

5 0

Answer:

D c < e

Step-by-step explanation:

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Choose the slope-intercept form of 3x + 2y = 5.

Norma-Jean [14]

Answer:

$y=\frac{-3}{2}x +\frac{5}{2} \\or \\y=\frac{5}{2} -\frac{3}{2} x$

Step-by-step explanation:

slope-intercept form is: $y= mx+b$

3x + 2y = 5.

rearrange

$2y=5-3x\\y=\frac{5}{2} -\frac{3x}{2}$

5 0

4 years ago

Read 2 more answers

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

Please help me (please dont send links)

Burka [1]

Answer:

Part A

79.4

Part B

Part C

The science class

Step-by-step explanation:

The linear function representing the average test score in the math class, after taking x number of tests, f(x) = 0.2·x + 79

The science class average test score, after taking x number of tests, is given by the linear function g(x)

The values of g(x) are presented as follows;

x; 1, 2, 3

g(x); 86, 84, 82

Part A

By using the given function for the test average for the math class, f(x), when x = 2, we have;

f(2) = 0.2 × 2 + 79 = 79.4

The test average for the math class after completing test 2 = 79.4

Part B

The test average for the science class after completing test 2 from the table is 84

Part C

After completing test 4, the test average for the math class, f(4), is given as follows;

f(4) = 0.2 × 4 + 79 = 79.8

The test average for the science class after the completing test 4 is found by noting that the test average, g(x) decreases by 2 for each increase in the number of test taken, x, by 1

Given that the test average of the science, g(3) class after taking test 3 is 82, the test average after taking test 4, g(4) = g(3) - 2 = 82 - 2 = 80

g(4) = 80

Therefore, after completing test (4), the science class has a higher test average g(4) = 80, than the math class f(x) = 79.8

3 0

3 years ago

Which answer does NOT correctly describe the graph of y = 5x + 12?

Dafna11 [192]

Answer:

The graph contains the point (5, 12) does NOT correctly describe the graph of y = 5x + 12

Solution:

Given, linear equation in two variable is y = 5x + 12.

We have to select the option that incorrectly describes about given equation.

Now, we have to check one by one option.

a) The line has a constant rate of change.

As the given line is an linear equation it will have constant slope. So this option states correctly

b) The line crosses the y-axis 12 units above the origin

When a line crosses y – axis it x value becomes 0 → y = 5(0) + 12 → y = 12

So, the line crosses the y – axis 12 units above the origin, so this option states correctly.

c) The graph contains the point (5, 12)

To contain (5, 12) in that line → 12 - 5(5) + 12 = 0 but -1 ≠ 0

So, this option is incorrect.

Hence, option c incorrectly describes about the graph.

7 0

3 years ago

In how many ways can 3 desserts be chosen in any order from a menu of 10?

AnnyKZ [126]

(1 × 10) + (2 × 10) + (3 × 10) =

10 + 20 + 30 = 60 different ways.

8 0

3 years ago