Question

A cliff diver strikes the water with a velocity of 32 square root 5 feet per second. Find the height which the diver dove. V=square root 2gh

Answer 1

Answer:

80

Step-by-step explanation:

equation $v=\sqrt{2gh}$

v = $32\sqrt{5}$ feet/s

g = 32 feet/s^2

plug in values

$32\sqrt{5}$ = $\sqrt{2*32*h}$

$\sqrt{32^{2}} * \sqrt{5} = \sqrt{32^{2}*5} = \sqrt{2*32*h}$

$32^2 * 5 = 2 * 32 * h$

32 * 5 = 2h

h = 32 * 5 / 2

h = 80