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3 years ago

11

Solve the equation: 3.2(s+10)=32

2 answers:

Lelechka [254]3 years ago

8 0

3.2(s+10)=32

3.2s+20=32

6s+20=32

6s=12

s=2

Dvinal [7]3 years ago

4 0

3.2s+32=32
-32
3.2s=0
-3.2
s=-3.2

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Given,

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Differentiating the equation to find maximum area

$\frac{d}{db}(\left ( k/2-b \right )b)=\frac{\partial 456}{\partial b}$

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$k=4b$

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To find $maxima$ again differentiating

$\frac{\partial A^2 }{\partial b^2}=\frac{\partial \left ( k/2-2b \right )}{\partial b}$

$\frac{\partial A^2 }{\partial b^2}$

The area is maximum when l=b

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$=2\sqrt{114}\times 3\times 12+2\sqrt{114}\times 7$

$=72\sqrt{114}+14\sqrt{114}$

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$=\$ 918.22873$

Dimension of rectangular garden

$\left ( l,b \right )=(21.3541,21.3541)$

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