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Verizon [17]
3 years ago
11

Solve the equation: 3.2(s+10)=32

Mathematics
2 answers:
Lelechka [254]3 years ago
8 0
3.2(s+10)=32

3.2s+20=32

6s+20=32

6s=12

s=2
Dvinal [7]3 years ago
4 0
3.2s+32=32
-32
3.2s=0
-3.2
s=-3.2
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A rectangular garden of area 456 square feet is to be surrounded on three sides by a brick wall costing $ 12 per foot and on one
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Answer:

l=2\sqrt{114}feet    b=2\sqrt{114}feet      \left ( l,b \right )=(21.3541,21.3541)

Step-by-step explanation:

Given,

Area of garden=456 square feet

Brick wall  cost three sides =\$ 12 per foot

fencing cost of one side=\$ 7 per foot

Let length and breadth of rectangular field is          (l,b) feet

For minimizing the cost of material perimeter of garden should be minimum and area of garden is more.

Perimeter of garden=2\left ( l+b \right )=k

l+b=k/2

l=k/2-b

A=l\times b=456

A=\left ( k/2-b \right )b=456

Differentiating the equation to find maximum area

\frac{d}{db}(\left ( k/2-b \right )b)=\frac{\partial 456}{\partial b}

k/2-2b=0

k=4b

l=4b/2-b

l=b

To find maxima  again differentiating

\frac{\partial A^2 }{\partial b^2}=\frac{\partial \left ( k/2-2b \right )}{\partial b}

\frac{\partial A^2 }{\partial b^2}

The area is maximum when    l=b

and perimeter is minimum

l\times b=456

b^{2}=456

b=2\sqrt{114}feet

l=2\sqrt{114}feet

 Cost material

=2\sqrt{114}\times 3\times 12+2\sqrt{114}\times 7

=72\sqrt{114}+14\sqrt{114}

=\$ 86\sqrt{114}

=\$ 918.22873

Dimension of rectangular garden

\left ( l,b \right )=(21.3541,21.3541)

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Step-by-step explanation:

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The sum of a number and 7 is 35
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Well, 7 times 5 is 35  so if that's the case there's your answer.
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