All categories

2 years ago

Help me please help me please please please

Mathematics

1 answer:

Vladimir79 [104]2 years ago

4 0

Answer: 1,5

Since the arc equals 2 times angle, the answer will be 90 Degrees which approximately equals to 1.5

You might be interested in

A car travelling at a constant speed travels 90km in 50 min .How far travelling at the same constant speed will the car travel i

vovikov84 [41]

Answer:

261 km

Step-by-step explanation:

given,s=constant

d1/T1=d2/T2

d1=90km,t1=50 min

d2=? ,t2=(120+25)min

=145min

therefore,d2=(90×145)/50

=261 km

6 0

3 years ago

Phil has 19 other students in his math class. During class one day, the teacher asks for a volunteer to come up to the board. If

Stolb23 [73]

Answer:

1/20

Step-by-step explanation:

if you do all kids there is 20. you have a 1 out of 20 people change so plz give brainest answer

7 0

3 years ago

Read 2 more answers

PLease help ................................................................

choli [55]

Answer:

if it is an a or b B is the best answer but if it a true of false. the answer is true

Step-by-step explanation:

4 0

3 years ago

sara says. "if you subtract 14 from my number and multiply the difference by -4, the result is -80." What is Sara's number?

statuscvo [17]

Answer:

Step-by-step explanation:

-80/-4=20+14=6

5 0

3 years ago

Read 2 more answers

I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr

Illusion [34]

Answer:

<h2><u>question 1</u></h2>

$n^{2} - 20n -96 = 0$

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

in the form $ax^{2} +bx +c = 0$

= $x^{2} +12x - 48$

make use of the formula :

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

replace values to make 2 equations :

1. $\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1}$ = 3.17

2. $\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1}$ = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

in the form $ax^{2} +bx +c = 0$

this becomes $5b^{2} -20b-18-7$

= $5b^{2} -20b-25$

can simplify by 5

= $b^{2} -4b-5 =0\\$

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0

3 years ago

Read 2 more answers