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nika2105 [10]
3 years ago
9

What is 954 divided by 46?? Give me a whole number and a remander Ex:

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

20,  remainder of 34

Step-by-step explanation:

   0 2 0

4 6 9 5 4

 − 0    

   9 5  

 − 9 2  

     3 4

   −   0

     3 4

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Which pair of triangles can be proven congruent by SAS?
ivolga24 [154]

Answer:

Second option

Step-by-step explanation:

They have two congruent pairs of sides and one congruent pair of angles.

4 0
2 years ago
What is the answer for this math?​
Westkost [7]

Answer:

x=-4.992 and x=-0.434

Step-by-step explanation:

we have    

\frac{\sqrt{3x+15}}{5}=2^{x}

we can divide the equation above into two equations

so

y=\frac{\sqrt{3x+15}}{5} ----> equation A

y=2^{x} ----> equation B

Solve by graphing

The solutions of the system are the x-coordinates of the intersection points both graphs

using a graphing tool

The solutions are x=-4.992 and x=-0.434

see the attached figure

6 0
3 years ago
Express 0.3°8° in form a/b where by b#0​
Harlamova29_29 [7]

Answer:

0.3° = 0.3π/180

8° = 2π/45

Multiplying both

0.3π/180×2π/45

3/10π/180 × 2π/45

You will get

π/300 × π/45

= π²/13500 where a = π² b= 13500

Hope this helps.

4 0
3 years ago
Find the distance between lines 8x−15y+5=0 and 16x−30y−12=0.
AlladinOne [14]

Answer:

The distance between the two parallel lines is 11/17 units

Step-by-step explanation:

we have

8x-15y+5=0 -----> equation A

16x-30y-12=0 ----> equation B

Divide by 2 both sides equation B  

8x-15y-6=0 ----> equation C

Compare equation A and equation C

Line A and Line C are parallel lines with different y-intercept

step 1

Find the slope of the parallel lines (The slope of two parallel lines is the same)

8x-15y+5=0

15y=8x+5

y=\frac{8}{15}x+\frac{1}{3}

the slope is

m=\frac{8}{15}

step 2

Find the slope of a line perpendicular to the given lines

Remember that

If two lines are perpendicular then their slopes are opposite reciprocal (the product of their slopes is -1)

m1*m2=-1

we have

m1=\frac{8}{15}

therefore

m2=-\frac{15}{8}

step 3

Find the equation of the line perpendicular to the given lines

assume any point that lie on line A

y=\frac{8}{15}x+\frac{1}{3}

For x=0

y=\frac{1}{3}

To find the equation of the line we have

point\ (0,1/3)  ---> is the y-intercept

m=-\frac{15}{8}

The equation in slope intercept form is

y=-\frac{15}{8}x+\frac{1}{3} -----> equation D

step 4

Find the intersection point of the perpendicular line with the Line C

we have the system of equations

y=-\frac{15}{8}x+\frac{1}{3} ----> equation D

8x-15y-6=0 ----> y=\frac{8}{15}x-\frac{2}{5} ----> equation E

equate equation D and equation E and solve for x

\frac{8}{15}x-\frac{2}{5}=-\frac{15}{8}x+\frac{1}{3}

\frac{8}{15}x+\frac{15}{8}x=\frac{1}{3}+\frac{2}{5}  

Multiply by 120 both sides to remove fractions

64x+225x=40+48

289x=88

x=88/289

Find the value of y

y=-\frac{15}{8}(88/289)+\frac{1}{3}

y=-\frac{206}{867}

the intersection point is (\frac{88}{289},-\frac{206}{867})

step 5

Find the distance between the points (0,\frac{1}{3}) and (\frac{88}{289},-\frac{206}{867})

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

d=\sqrt{(-\frac{206}{867}-\frac{1}{3})^{2}+(\frac{88}{289}-0)^{2}}

d=\sqrt{(-\frac{495}{867})^{2}+(\frac{88}{289})^{2}}

d=\sqrt{(\frac{245,025}{751,689})+(\frac{7,744}{83,521})}

d=\sqrt{\frac{314,721}{751,689}}

d=\frac{561}{867}\ units

Simplify

d=\frac{11}{17}\ units

therefore

The distance between the two parallel lines is 11/17 units

see the attached figure to better understand the problem

4 0
3 years ago
If mrs.burks spent $3.87 on grapes at kroger and bought 3.05 , pounds how much was each pound.
Mkey [24]

Answer:

$1.27

Step-by-step explanation:

The cost of a unit item can be found by dividing the total amount paid by the total quantity given. In this case, the total quantitu is given as 3.05 pounds and the price is also given.

Since 3.05 pounds cost a total of $3.87 then the cost per pound would be given by dividing the amount paid by the pounds given

$3.87÷3.05=$1.2688524590163 per pound

Rounded off, then 1 pound is approximately $1.27

4 0
3 years ago
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