Answer:
Therefore you can wear your rings in =336 ways
Step-by-step explanation:
Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy
Given that you have 3 different rings.
We have total 10 figures.
But you don't wear ring on your thumbs.
We have 2 thumbs.
So you can wear rings on (10-2) = 8 figures.
The ways of wearing of first ring is = 8
The ways of wearing of second ring is = 7
The ways of wearing of third ring is = 6
Therefore you can wear your rings in =(8×7×6)
=336 ways
Answer:
the set of all real numbers
Step-by-step explanation:
f(x) = 3X + 9 is a polynomial, and so both the domain and the range are "the set of all real numbers."
None of your answer choices match this. Check with your teacher if you can.
I assume it is the last one, 3n^2, because the degree is the exponent, which is two and the three is the coefficient, which is next to the variable, plus it is a monomial, so there is only one term, eliminating the first two, the third one is just reversed. Therefore, the answer should be the last one. Hope this helps. :)
Answer:
x = 22.5
Step-by-step explanation:
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
