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3 years ago

Classify triangle by its Aangles and sides

Mathematics

1 answer:

goldenfox [79]3 years ago

7 0

Answer:

Triangle is a three(3) sided shape i.e it has 3 sides and angles. Triangle can classify based on its side (length and equality) and size of its angles.

Step-by-step explanation:

A, Classification by sides: There are three types of triangle base on sides. These are:

1. Scalene Triangle : This describe triangle that has none of its side to be equal. i.e none of the three sides has no equal length.

2. Isosceles Triangle : This describe triangle that has two of its side equal. Also two of the angles are equal.

3. Equilateral Triangle : This describe triangle that has all its side equal i.e all three sides have equal length. Also all angles are of equal sizes.

B. Classification by size of angle: There are four types of triangle base on classification by angle:

1. Acute Triangle : This describe triangle with all three angles less than 90 degree.

2. Obtuse Triangle : This describe triangle that has one of its angle greater than 90 degree

3. Right Angled Triangle : This describe triangle with one of its angle equal 90 degree.

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Help please<br> what is<br>

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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barxatty [35]

Answer:

B - symmetrical

Step-by-step explanation:

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6 0

3 years ago

I need help plz help

grin007 [14]

Answer:

12,6,0,-6,-12

Step-by-step explanation:

Plug the x values into the equation

y=-3x

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3 years ago

{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5

lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:

one solution
no solution
infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

$4x-2y+5z = 6$
$3x+3y+8z = 4$
$x-5y-3z = 5$

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2: Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3: Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists

3 0

3 years ago