Ask question

Ask question

All categories

3 years ago

14

HELP PLEASE!!

1 answer:

ANTONII [103]3 years ago

5 0

<span>Volume of the Sphere V = 4/3pi x r^3 So when diameter d = 3 inches => r = 1.5 inches volume of the sphere = 4.188 x r^3 = 4.188 x 1.5^3 = 14.14 in So when diameter d = 8 inches => r = 4 inches volume of the sphere = 4.188 x r^3 = 4.188 x 4^3 = 268.03 in So when diameter d = 9 inches => r = 4.5 inches volume of the sphere = 4.188 x r^3 = 4.188 x 4.5^3 = 381.63 in value for option (a) is 3 x 14.14 = 42.42 inches value for option (b) is 268.03 inches value for option (c) is 381.63 / 2 = 190.815 inches So the correct option would be (b)</span>

You might be interested in

Leo the rabbit hops 1 or 2 stairs how many different ways can he climb 10 stairs

noname [10]

He can climb 2 ways
First - hopping 10 times
Second - hopping 5 times

4 0

3 years ago

Enter the ordered pair for the vertices for Rx-axis(QRST).

mash [69]

Given:

The vertices of a polygon QRST are T(-2, 3), Q(1, 5), R(3, -1) and S(0, 0).

To find:

The vertices for $R_{x-axis}(QRST)$ .

Solution:

The rule $R_{x-axis}(QRST)$ represents refection of polygon QRST across the x-axis.

If a figure is reflected across the x-axis, then

$(x,y)\to (x,-y)$

Using this rule, we get

$T(-2,3)\to T'(-2,-3)$

$Q(1,5)\to Q'(1,-5)$

$R(3,-1)\to R'(3,1)$

$S(0,0)\to S'(0,0)$

Therefore, the vertices for $R_{x-axis}(QRST)$ are T'(-2, -3), Q'(1, -5), R'(3, 1) and S'(0, 0).

7 0

3 years ago

Hunter had 3⁄8 of a pizza. He gave 2⁄3 of the pizza to his friend Taylor. What fraction of the whole pizza did Taylor get?

Nikitich [7]

Answer:

1/4

Step-by-step explanation:

3/8 * 2/3 = 6/24 = 1/4

AAAAAAAA .... whole pizza

AAA ... Hunter had

AA ... tylor get

4 0

3 years ago

Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=

Nezavi [6.7K]

Given:

The system of equations is

$y=2x-5$

$2y-4x=?$

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

$y=2x-5$

$2y-4x=k$

Taking all the terms on the left side, the given equations can be rewritten as

$-2x+y+5=0$

$-4x+2y-k=0$

The system of equations $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$ have infinitely many solutions if

$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$

We have,

$a_1=-2,b_1=1,c_1=5$

$a_2=-4,b_2=2,c_2=-k$

Now,

$\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}$

$\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}$

$\dfrac{1}{2}=\dfrac{5}{-k}$

On cross multiplication, we get

$-k=10$

$k=-10$

Therefore, the missing value is -10.

6 0

3 years ago

-n+(-3)+3n+5<br><br> Combing like terms :

Karolina [17]

Answer: 2n + 2 should be your answer

3 0

3 years ago