Fun a copra cereals, Pedro latiendo no se abre (haste /pronto ) las 8:00. Tuve que Esperanto media hora.

Can someone write me a thesis statement for "the kite runner" using 'the past tends to catch up to you' as the theme please 25 p

romanna [79]

Answer:

ok i will answers agin when done

Explanation:

8 0

2 years ago

What is the definition of poverty (both absolute and relative)? Where does the notion of "dignity" fit in? What are some situati

sveticcg [70]

Dignity can play a role it should not. The dignity comes into effect if and when a party concerned is unable to participate fully in an activity of society in the event of insufficient funds for any item/purchase/luxury suggestively needed for this activity.

3 0

2 years ago

Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th

lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

$C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2$

Finding the boundaries of the function gives;

$0\times e^{4-0^2} = 0$ and $2\times e^{4-2^2} = 2$

At t = 1, we have $1\times e^{4-1^2} = e^{3} = 20.086$

We find the maximum point as follows;

$\frac{\mathrm{d} \left (t\times e^{4-t^2} \right )}{\mathrm{d} x}=0$

From which we have;

$\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0$

$e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0$

$e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\$

$e^{4-t^2}=0$ or $(1 - 2\times t^2 })=0$

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for 0 ≤ t ≤ 0 1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0

2 years ago

Does Hatchet have instructional value as a survival guide?

Rasek [7]

Answer:

It probably does because a hatchet is also dangerous and it should be used for the right reasons

Explanation:

It should be used at a specific age range, and for specific sizes of trees

5 0

2 years ago

Read 2 more answers

If A:B = 3:4 and B:C = 2:3, find A:B:C.

ozzi

Answer:

its a i think

Explanation:

a:b=2:3b:c=4:3=(4∗34:3∗34)=3:94a:b:c=2:3:94=8:12:9

4 0

2 years ago