All categories

3 years ago

6. (5 points) The following instruction sequence is to be executed:

Computers and Technology

1 answer:

muminat3 years ago

8 0

Answer:

11 cycles.

Explanation:

One interesting thing to observe in this is that, there is no data hazard because here in any of the two consecutive instruction, they do not share any common register and hence no collision.

Also assuming each this program starts with address 0, so that condition checking at the end which is "bne $7, $4, 0x040" will not lead to branching which repeats the loop. Which means this sequence of 7 instructions run only once.

Now if there is no pipeline hazard (which is the case here) and there are n instruction with s stages in pipeline with each stage take 1 cycle, then total cycle required to finish the program will be n+(s-1)=n+s-1

Here number of instruction n=7 and in multicycle datapath usually pipeline stages s=5.

Then number of cycles needed to execute this sequence will be = 7 +5 -1 = 11 cycles

You might be interested in

Discuss the role of the concept behind the "Internet of Things (IoT)" in today's digitally connected society.

AlekseyPX

Answer:

IoT Definitions: The term Internet of Things generally refers to scenarios where network connectivity and computing capability extends to objects, sensors and everyday items not normally considered computers, allowing these devices to generate, exchange and consume data with minimal human intervention.

Explanation:

hope that helps

7 0

3 years ago

Which of the following statements is false? a. Racks and bins are examples of storage equipment. b. Automation refers to equipme

svp [43]

Answer:

b. Automation refers to equipment that complements, rather than replaces, human contact.

3 0

3 years ago

PLEASEE HELPP.... QUESTION... how does coding impact your life

nataly862011 [7]

Answer: It allows us to do everyday tasks on the internet

Explanation: We wouldn’t be able to email, research, etc without coding!

6 0

3 years ago

Read 2 more answers

How impactful were shipping errors on customer questions.

Bumek [7]

Answer:

It's due to damage of goods

7 0

2 years ago

Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i

LenKa [72]

Answer:

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#define BUFSIZE 16

int main(){

//pipe descriptors

char msg[BUFSIZE];

char buf[BUFSIZE];

int pipefd[2];

if(pipe(pipefd) == -1){

//pipe creation error

perror("pipe");

exit(EXIT_FAILURE);

}

//pipe creation successfull

//write four messages

sprintf(msg , "apple");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

sprintf(msg , "boy");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

sprintf(msg , "cat");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

sprintf(msg , "dog");

write(pipefd[1], msg, BUFSIZE);

printf("Written %s\n", msg);

//read

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("Read: %s\n", buf);

close(pipefd[0]);

close(pipefd[1]);

return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

//pipe descriptors

char msg[BUFSIZE];

char buf[BUFSIZE];

int pipefd[2];

if(pipe(pipefd) == -1){

//pipe creation error

perror("pipe");

exit(EXIT_FAILURE);

}

//pipe creation successfull

//write four messages

if(fork() == 0){

//this is child

//close unused write end

close(pipefd[1]);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading first message. Content is %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading second message. Content is %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading third message. Content is %s\n", buf);

read(pipefd[0], buf, BUFSIZE);

printf("This is child process reading fourth message. Content is %s\n", buf);

close(pipefd[0]);

//exit from child

exit(EXIT_SUCCESS);

}

//this is parent process

//close unused read end

close(pipefd[0]);

sprintf(msg , "apple");

printf("This is parent process. Writing first message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

sprintf(msg , "boy");

printf("This is parent process. Writing second message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

sprintf(msg , "cat");

printf("This is parent process. Writing third message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

sprintf(msg , "dog");

printf("This is parent process. Writing fourth message into pipe\n");

write(pipefd[1], msg, BUFSIZE);

close(pipefd[1]);

//wait for child

wait(NULL);

return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

//alarm fired writing blocked

printf("Write blocked after %llu characters\n", size);

exit(EXIT_SUCCESS);

}

int main(){

//pipe descriptors

int pipefd[2];

if(pipe(pipefd) == -1){

//pipe creation error

perror("pipe");

exit(EXIT_FAILURE);

}

//install handler

sigset_t mask , prev;

sigemptyset(&mask);

sigaddset(&mask , SIGALRM);

sigprocmask(SIG_BLOCK , &mask , &prev);

Sigaction new_action;

sigemptyset(&new_action.sa_mask);

new_action.sa_flags = SA_RESTART;

new_action.sa_handler = alarmhandler;

sigaction(SIGALRM , &new_action , NULL);

sigprocmask(SIG_SETMASK , &prev, NULL);

while(1){

//print size on multiple of 4

if(size != 0 && size % 1024 == 0){

printf("%llu characters in pipe\n", size);

}

//reset previous alarm

alarm(0);

//set new alarm for 5 seconds

alarm(5);

//write to pipe one character

write(pipefd[1], "A", sizeof(char));

size++;

}

return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0

3 years ago