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3 years ago

The value of 3(x+3)^2 when x=-4

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

8 0

3(4+3)^2=3(7)^2 3(49)=147

masha68 [24]3 years ago

8 0

Answer:

Step-by-step explanation:

Substituting -4 for x in 3(x+3)^2, we get 3(-4 + 3)^2, or 3(-1)^2, or just 3.

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If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes

Keith_Richards [23]

You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.

4 0

4 years ago

Read 2 more answers

there are 16 crayons in each box let x represent the number of boxes of crayons and let y represent the total number of crayons

Ivanshal [37]

Answer:

16x?

the question is confusing

8 0

3 years ago

How many solutions does 5(x+2)-3=3x-8x+7 have

Kryger [21]

Answer:

One solution.

Step-by-step explanation:

Step 1: Write equation

5(x + 2) - 3 = 3x - 8x + 7

Step 2: Solve for x

Distribute 5: 5x + 10 - 3 = 3x - 8x + 7

Combine like terms: 5x + 7 = -5x + 7

Add 5x to both sides: 10x + 7 = 7

Subtract 7 on both sides: 10x = 0

Divide both sides by 10: x = 0

Step 3: Check

Plug in x to verify if it's a solution.

5(0 + 2) - 3 = 3(0) - 8(0) + 7

5(2) - 3 = 7

10 - 3 = 7

7 = 7

3 0

4 years ago

Find the LCD of the rational expression Problems 3,4,5 Please help!!!

horrorfan [7]

The LCD of the rational expressions are 30x^5, (3x - 1)(x + 6) and (x + 3)(x + 5)^2

<h3>How to determine the LCD of the rational expressions?</h3>

Expression 1

The rational expressions are given as:

3/10x^2 and x + 7/15x^5

Write out the denominators

10x^2 and /15x^5

Expand each of the denominator.

10x^2 = 2 * 5 * x * x

15x^5 = 3 * 5 * x* x * x * x * x

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = 2 * 3 * 5 * x* x * x * x * x

Evaluate

LCD = 30x^5

Expression 2

The rational expressions are given as:

9/3x - 1 and 2x/x + 6

Write out the denominators

3x - 1 and x + 6

Expand each of the denominator.

10x^2 = 3x - 1

15x^5 = x + 6

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = (3x - 1)(x + 6)

Expression 3

The rational expressions are given as:

8x/(x + 5)^2 and 4x + 1/x^2 + 8x + 15

Write out the denominators

(x + 5)^2 and x^2 + 8x + 15

Expand each of the denominator.

(x + 5)^2 = (x + 5) * (x + 5)

x^2 + 8x + 15 = (x + 3) * (x + 5)

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = (x + 3) * (x + 5) * (x + 5)

LCD = (x + 3)(x + 5)^2

Hence, the LCD of the rational expressions are 30x^5, (3x - 1)(x + 6) and (x + 3)(x + 5)^2