Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
Sec^2 x - 1 = tan^2x
Proof:
Sec^2x = 1+ tan^2x
1/cos^2x = 1 + sin^2x/cos^2x
<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting :
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side
Answer: -(x+8)(x-8)
Step-by-step explanation:
-(x^2-64)
x^2-8^2x^2
x^2-8^2=(x+8)(x-8)
-(x+8)(x-8)
Answer:
C.
Explanation: I guest it is base on my research but i dont have a solution peace
Answer:
8x² + 6x - 35
Step-by-step explanation:
A = (2x + 5)(4x - 7)
Front: 2x * 4x = <em>8x²</em>
Outside: 2x * (-7) = <em>-14x</em>
Inside: 5 * 4x = <em>20x</em>
Last: 5 * -7 = <em>-35</em>
Add up: <em>8x² - 14x + 20x -35</em>
Simplify: 8x² + 6x - 35