Answer:
28 pounds
Step-by-step explanation:
We have a total of 5 boxes, now we know that each box weighs 9 pounds, therefore:
Total weight = 5 * 9 = 45 pounds
Which means there are 45 pounds in total.
We are told that the limit is exceeded by 17 pounds. To find the limit weight, it is necessary to subtract the total weight and the excess:
45-17 = 28 pounds
Therefore, the maximum weight allowed per shipment is 28 pounds.
5^3=125; 2.5^2=6.25. So the answer to your first question is 125, and the second one is 6.25
The answer to this question is b
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8
As x approaches -inf f(x) -> -inf
and as x approaches inf, f(x) approaches +inf
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