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3 years ago

Thaddeus traded $3750 for British pounds, immediately changed his mind,

Mathematics

1 answer:

hram777 [196]3 years ago

5 0

1 pound = 1.28 dollar

We can multiply to find the amount he has.

3750 * 1.28 = $4800

Therefore, the answer is B.

Best of Luck!

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A dealer gains 16% by selling a mop for rs.78300.but due to competition in the market, he decides to make a profit of only 10%.

vesna_86 [32]

Answer:

The correct answer is - 72,349.2

Step-by-step explanation:

Given:

selling price = 7234.92

Initial profit = 16%

we know:

selling price = cost price + profit

Solution:

78300 = cp + 16*cp/100

profit = 78300*16/100 = 12528

cost price = 78300 - 12528 = 65772

then the profit on 10%

= 65772*10/100

= 6577.2

the new selling price = 65772+6577.2

= 72,349.2

3 0

3 years ago

1. What is the place value of the 1 in 1,234,567,890?

FrozenT [24]

Answer:

The place value of 1 in 1,234,567,890 is 1,000,000,000.

4 0

2 years ago

Read 2 more answers

How do you do this? Because i don't know how to do it :>

Sindrei [870]

Answer:

£ 7.95

Step-by-step explanation:

Let the total money = £ x

Money spend on drinks and cake = 1.45 + 1.20 = £ 2.65

Money left with her = (2/3) of x

So, money spend = (1/3) of x

$\dfrac{1}{3}*x= 2.65\\\\\\x=2.65*3\\\\$

x = £ 7.95

7 0

2 years ago

I have the question in a screengrab. Thank you, whoever helps me.

nata0808 [166]

To simplify

$\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}$

we need to use the fact that

$\sqrt[4]{x^4}=|x|$

Why the absolute value? It's because $(-x)^4=(-1)^4x^4=x^4$ .

We start by rewriting as

$\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}$

$\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}$

Since $x\neq0$ , we have $\dfrac xx=1$ , and the above reduces to

$\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}$

Then we pull out any 4th powers under the radical, and simplify everything we can:

$\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}$

$\dfrac1{|2y|}\sqrt[4]{3x^2}$

where $y>0$ allows us to write $\dfrac yy=1$ , and this also means that $|y|=y$ . So we end up with

$\dfrac{\sqrt[4]{3x^2}}{2y}$

making the last option the correct answer.

7 0

3 years ago

Which statements are true about the place values in the number 99.999?

dalvyx [7]

A and B are correct... reason is because hundredths is 1/10 to tenths and tenths are 10 times bigger than hundredths. C and D are wrong.

Hope this helped!

Nate

4 0

3 years ago