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Igoryamba
3 years ago
9

PLEASE HELP ME!!  i have to answer this question fast please help

Mathematics
1 answer:
otez555 [7]3 years ago
5 0
Y=-1/4x+7.5 is the right equation
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Pls help meh<br> i will give brainlyest
MissTica

Answer:

The answer is 75

can me be brainliest?

Step-by-step explanation:

PEMDAS

20x4-100/20

80-5

75

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3 years ago
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Do the expressions have only one term. write yes or no<br> 1. x<br> 2. p/4<br> 3. 23-w
MrRa [10]
They all only have 1 term.
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3 years ago
Write the following as an inequality.
miss Akunina [59]

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7<u>></u>x<u>></u>-3

Step-by-step explanation:

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3 years ago
Suppose the lifetime of a cell phone battery is normally distributed with a mean of 36 months and a standard deviation of 2 mont
solong [7]

Answer:

They should guarantee the lifetime of their batteries for 32 months.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 36 months and a standard deviation of 2 months.

This means that \mu = 36, \sigma = 2

If the company wants to replace no more than 2% of all batteries, for how many months should they guarantee the lifetime of their batteries?

The guarantee should be the 2th percentile of lengths, which is X when Z has a pvalue of 0.02. So X when Z = -2.054.

Z = \frac{X - \mu}{\sigma}

-2.054 = \frac{X - 36}{2}

X - 36 = -2.054*2

X = 31.89

Rounding to the closest month, 32.

They should guarantee the lifetime of their batteries for 32 months.

3 0
3 years ago
2/5 of the population has blood type A. 23/50 have blood type O. What fraction of the population had either blood type A or O?
emmainna [20.7K]
25/55 people have either A or O
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3 years ago
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