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lubasha [3.4K]
2 years ago
7

William looks around at an assembly. He notices his younger sister to his right and his older brother 8 meters ahead of him. If

William's brother and sister are 10 meters apart, how far apart are William and his younger sister?
Mathematics
1 answer:
vovangra [49]2 years ago
3 0
Answer: 6

Explanation: By this word problem, you can use Pythagorean theorem.
Using 8 as a leg. And the 10 as the hypotenuse.

8^2 + b^2 = 10^2
64 b^2 = 100

100 - 64 = 36.
36 being a perfect square, = 6.
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The ratio of students who wear glasses to the total number of students in the class is 2:5 if there are 14 students who wear gla
vazorg [7]

Answer:

35 students in the class.

Step-by-step explanation:

If there are 5 students in the class, then 2 of them would wear glasses and 3 of them wouldn't. (Equation 1)

Now, there are 14 students how are wearing glasses.

We just times the whole Equation 1 by 7.

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8 0
2 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
____ ) 43 − 2
Ivan

Answer:

ly/3fcEdSx link for answer

3 0
2 years ago
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