All categories

3 years ago

Evaluate the given algebraic expression for x=3 and y=3 x^2y^2

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

x^2y^2

3^2 *3^2

9*9

Choice D

You might be interested in

Bring the fraction a/a−4 to a denominator of 16−a^2<br><br> really do appreciate this thx

RSB [31]

Answer:

-a(a+4)/(16 - a²)

Step-by-step explanation:

a/(a - 4) Multiply by (a + 4)/(a + 4)

= a(a + 4)/[(a – 4)(a + 4)] Multiply the denominatorator terms

= a(a + 4)/(a² - 16) Multiply by -1/(-1)

= -a(a+4)/(-a² + 16) Reorder terms in denominator

= -a(a+4)/(16 - a²)

5 0

3 years ago

What is the distance around a triangle that has measuring 2 1/8 feet,3 1/2 feet, 2 1/2 feet

N76 [4]

Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8

Hope this will help you!

3 0

3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

Help me pleaseeeeeeeee

serg [7]

The answer is (((((A ))))))

4 0

3 years ago

Airline companies raise and lower their ticket prices based on the supply and demand. Due to high numbers of fliers, one company

vovikov84 [41]

The raised price represents 110% of the original price (100% plus the extra 10%)

A percentage is converted into a decimal multiplier by dividing by 100:
$\frac{110}{100} = 1.10$

To clarify the final stage, consider this (where $n$ is the original price):
$n * 1.10 = 192.50$
$1.10n = 192.50$

From here, basic algebraic rules make solving for $n$ easy:
$n = \frac{192.50}{1.10} = 175$

Therefore the original price of a ticket was $175

3 0

3 years ago