Evaluate the given algebraic expression for x=3 and y=3 x^2y^2

Change 0.1928 to a percent

Salsk061 [2.6K]

B is the right choice.

You move the point to two spaces right, making 19.28 (percent).

8 0

3 years ago

Read 2 more answers

If a test is worth 90 points and I got 12/15 questions right then what would my grade be?

Yuki888 [10]

Answer: 80

Step-by-step explanation:

6 0

3 years ago

15% of 9 dollars is how many dollars

Ket [755]

9 .............. 100%
x................ 15%

100x = 15 . 9
100x = 135
x = <u>135</u>
100
x = 1,35

6 0

3 years ago

One hour on earth is four hours on planet S.

Andreas93 [3]

Answer:

The answer is 60 hours.

Step-by-step explanation:

We could use proportions to solve.

$\frac{1 \: hour \: on \: earth}{4hours \: on \: planet \: s} = \frac{x}{240hours \: on \: planet \: s}$

$4 \times x = 4x \\ 1 \times 240 = 240$

$\frac{4x}{4} = \frac{240}{4} \\ x = 60$

3 0

3 years ago

Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â Suppose a small group of 11 Allen's humming

alexira [117]

Answer:

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=3.15$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=0.38$ represent the population standard deviation

n=11 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that $z_{\alpha/2}=1.28$

Now we have everything in order to replace into formula (1):

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

8 0

3 years ago