Mutiplying: the product is always 0
Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
Answer:
31.929
Step-by-step explanation:
29.95×6/100=1.797
29.95+1.797=31.929
Answer:
1: 47
2: 19
3: 7
4: 11
5: 31
Step-by-step explanation:
input the number next to F where x is. example: f(-2)= 8(-2)^2-4(-2)+7 and then solve using PEMDAS giving f(-2)=47 and so on.
Answer:
-2
Step-by-step explanation:
