Answer:
- equation: y = x+3
- inequality: y < x+3
Step-by-step explanation:
The slope of the line is 1 unit of rise for 1 unit of run, so ...
m = rise/run = 1/1 = 1
The y-intercept is 3 grid lines above the x-axis, so is (0, 3).
Then the equation of the line is ...
y = 1x +3
The inequality has that line as a boundary, but the y-values on the line are not part of the solution space. Only y-values below the line (less than those on the line) are in the solution. The inequality is ...
y < x +3
Answer:
There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.
To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.
Step-by-step explanation:
Suppose the equation of the straight line that passes through E and F is this:
y = 7x + 2
We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.
10 = 7(1) + 2 = 7 + 2 = 9
10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.
If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.
When you reflect the figure over the x-axis, you should have a new coordinate of (2,4) for A.
