Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
You have a higher chance of getting an even number than a multiple of three. There are 3 even numbers and only 2 multiples of three.
You know that it's a bot when it says "explanation in file".
They forgot to put a question, there's nothing to answer...
Answer:
Hey there!
Let the cost of one uniform be c, so the expression becomes
c+13+11+18
Thus, we have c+42
Hope this helps :)