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Ugo [173]
3 years ago
8

A store purchased a DVD for $15.00 and sold it to a customer for 50% more than the purchase price. The customer was then charged

a 7% tax when the DVD was sold. What was the customer's total cost for the DVD? Round your answer to the nearest cent.
Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

$24.08

Step-by-step explanation:

Step one:

given data

A store purchased a DVD for $15.00 and sold it to a customer for 50% more than the purchase price.

The increase is

=50/100*15

=0.5*15

=$7.5

Selling price

= 7.5+15

= $22.5

The tax is 7%

=7/100*22.5

=0.07*22.5

=1.575

The total cost/ amount paid is

1.575+22.5

=$24.075

=$24.08

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2887301

—————

Solve the initial value problem:

   dy
———  =  2xy²,      y = 2,  when x = – 1.
   dx


Separate the variables in the equation above:

\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
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Integrate both sides:

\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
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\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}


In order to find the value of  C₁  , just plug in the equation above those known values for  x  and  y, then solve it for  C₁:

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\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
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Substitute that for  C₁  into (i), and you have

\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
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So  y(– 2)  is

\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
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I hope this helps. =)


Tags:  <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

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