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mamaluj [8]
3 years ago
5

If a 12-sided regular polygon rotates about its center, at which angle of rotation will the image of the polygon coincide with t

he preimage?
A. 75°
B. 45°
C. 36°
D. 30°
Mathematics
2 answers:
Nikolay [14]3 years ago
6 0
ThE ANSWER IS d) 30 DEGREES
Andreas93 [3]3 years ago
3 0
D) 30

A polygon can rotate a total of 360. This one has 12 sides and 12 angles that are all congruent. So to coincide with original image, it must rotate 1/12 of the way around

360/12=30
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The length of a rectangle is 6 ft longer than its width. if the perimeter of the rectangle is 52 ft , find its area.
sveticcg [70]
Let its width be w and length= w+6
2(w+6+w)=52
4w+12=52
4w=40
w=10
Area=10*(10+6)=160
7 0
3 years ago
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

5 0
3 years ago
2 Points
Mashcka [7]

Answer:

C

Step-by-step explanation:

Factor: -7x^2 -5x+18

Factor -1 out of 7x^2 -5x +18:

−(7x^2+5x−18)

Factor.

1. 18 is negative, so a negative number multiplied by a postive number.

2. You can't factor 7, so 7x times x.

(7x−9)(x+2)

4 0
3 years ago
Ann is grouping 38 rocks.she can put them into groups of 10 rocks or as single rocks .what are the different ways Ann can group
photoshop1234 [79]

Answer:

3 and 8/10

Step-by-step explanation:

38/10=3.8 you can have three groups of 10 and 8/10 of another group

4 0
3 years ago
Can anybody tell me how to solve this
Lyrx [107]
The answer to your question is:  Yes, someone undoubtedly can.

Although you haven't asked to be told or shown how to solve it, I'm here
already, so I may as well stick around and go through it with you.


The sheet is telling you to find the solutions to two equations, AND THEN
DO SOMETHING WITH THE TWO SOLUTIONS.  But you've cut off the
instructions in the pictures, so all we have are the two equations, and
you'll have to figure out what to do with their solutions.

<u>First equation:</u>
                                   (2/5) x - 6 = -2
Add 6 to each side:
                                   (2/5) x = 4
Multiply each side by 5:
                                   2x = 20
Divide each side by 2 :
                                     <u>x = 10</u>

<u>Second equation:</u>
                                   -3y + 1/4 = 13/4
Subtract 1/4 from each side:
                                   -3y = 12/4
Multiply each side by 4 :
                                -12 y = 12
Divide each side by -12 :
                                      <u> y = -1</u>
5 0
3 years ago
Read 2 more answers
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