Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
1:
10=6
5=3
not sure
2:
triangle=16
circle=27
square=26
3: c
6: .78 per minute
7: they both have the same price one jaut has more ounces
7: they would make 10.56 dollars profit
Hello,
Area under the curve is 1.
So p(x>5)=1-p(x<5)=1-0.0625=0.9375
Answer A
Answer:
Mike drew the following figure in his notebook. What is the value of ? Show all work
Step-by-step explanation:
Is 288
Answer:
1000(1/20000) +
300(2/20000) +
10(20/20000) +
=
1800/20000 = .09
Step-by-step explanation:
Each ticket purchased is expected to win 9 cents
Each ticket purchased cost 75 cents
If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.
