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yawa3891 [41]
2 years ago
13

Help please god bless you!!!!!

Mathematics
2 answers:
Aleksandr-060686 [28]2 years ago
4 0
75 B because there’s a difference of 25 in each temperature interval
Arte-miy333 [17]2 years ago
4 0
The answer is 175 :)
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How do I solve this step by step?
Zinaida [17]

Answer:

45

Step-by-step explanation:

plug in 3 where the xs are

2(3)(6(3)-5(3))+(3)^2(5(3)-4(3)=45

2(3)=6

6(3)=18

-5(3)=15

(3)^2=9

5(3)=15

-4(3)=-12

8 0
3 years ago
Which graph represents the given equation?
Alchen [17]

9514 1404 393

Answer:

  A

Step-by-step explanation:

The axis of symmetry of quadratic ax²+bx+c is x=-b/(2a). For the given equation, the axis of symmetry is ...

  x = -4/(2(3/2)) = -4/3

The only graph with its vertex at x=-4/3 is graph A.

_____

<em>Additional comment</em>

You can also make the correct choice by evaluating the equation at a couple of different values of x. Convenient ones are x= -1, or 0, or +1. The value at x=0 is the y-intercept, (0, -2), which seems to be a point on all of the graphs. The value at x=1 is 3/2+4-2 = 3.5, which looks like it is only seen on graph A.

7 0
2 years ago
What is the probability of spinning once and having it land on either 2 or 8?
Aloiza [94]
If the highest number is 8 then the answer I think would be 1/8.
6 0
3 years ago
Rewrite expression as a single power<img src="https://tex.z-dn.net/?f=6%5E%7B4%7D%2A%206%5E%7B4%7D" id="TexFormula1" title="6^{4
victus00 [196]

Answer:

6^8

Step-by-step explanation:

6^4 * 6^4

We know that a^b * a^c = a^( b+c)

6^(4+4)

6^8

5 0
3 years ago
Read 2 more answers
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
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