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butalik [34]
3 years ago
9

3(x - 2) + 4 = 2x -1

Mathematics
2 answers:
Scrat [10]3 years ago
6 0

\text {Hi! Let's Solve this Equation!}

\text {The First Step is to Simplify the Equation:}

\text {3 becomes 3x. 3*-2=-6 so that becomes -6.}

\text {Add: -6+4=-2}

\text {Your new Problem should be: 3x+-6+4=2x-1}

\text {The Next Step is to Subtract 2x:}

\text {3x-2-2x=2x-1-2x}\\\text {x-2=-1}

\text {The Final Step is to Add 2:}

\text {x-2+2=-1+2}

\text {Your Answer should be:}

\fbox {x=1}

\text {Best of Luck!}

\text {-LimitedX}

romanna [79]3 years ago
5 0

Answer:

- 1

Step-by-step explanation:

Step 1:

3 ( x - 2 ) + 4 = 2x - 1        Equation

Step 2:

3x - 6 + 4 = 2x - 1      Multiply

Step 3:

3x - 2 = 2x - 1     Combine Like Terms

Step 4:

3x = 2x - 1 + 2   Add 2 on both sides

Step 5:

3x = 2x - 1    Combine Like Terms

Step 6:

x = - 1     Subract 2x on both sides

Answer:

x = - 1

Hope This Helps :)

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he radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had lost
elena-s [515]

Answer:

The bones were 12,485 years old at the time they were​ discovered.

Step-by-step explanation:

Amount of the element:

The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The radioactive element​ carbon-14 has a​ half-life of 5750 years.

This means that A(5750) = 0.5A(0), and we use this to find k. So

A(t) = A(0)e^{-kt}

0.5A(0) = A(0)e^{-5750k}

e^{-5750k} = 0.5

\ln{e^{-5750k}} = \ln{0.5}

-5750k = \ln{0.5}

k = -\frac{\ln{0.5}}{5750}

k = 0.00012054733

So

A(t) = A(0)e^{-0.00012054733t}

A scientist determined that the bones from a mastodon had lost 77.8 ​% of their​ carbon-14. How old were the bones at the time they were​ discovered?

Had 100 - 77.8 = 22.2% remaining, so this is t for which:

A(t) = 0.222A(0)

Then

0.222A(0) = A(0)e^{-0.00012054733t}

e^{-0.00012054733t} = 0.222

\ln{e^{-0.00012054733t}} = \ln{0.222}

-0.00012054733t = \ln{0.222}

t = -\frac{\ln{0.222}}{0.00012054733}

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The bones were 12,485 years old at the time they were​ discovered.

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Step-by-step explanation:

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Answer:

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