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Sliva [168]
3 years ago
9

At a dog competition, a dog is awarded 10 points if it runs through 4 pipes, makes 10 jumps, and walks on 2 beams. If Roofy gets

9 points after missing a pipe and Ralph gets 7 points after missing a pipe and a beam, how many points does Butch get if he misses 4 jumps but goes through the rest of the exercises perfectly?
Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer:

Butch should be awarded with 9,2 points

Step-by-step explanation:

Roofy gets 9 points out of 10 missing only a pipe, that means that each pipe is awarded with 1 point

Ralph gets 7 points out of 10 missing one pipe ( 1 point ) and 2 points missing a beam

So points are awarded as follows

1 point by pipe              then 4 points   for    4 pipes

2 points by beam         then  4 points  for     2 beams

We just have 2 points to award 10 jumps then each jump is awarded by 0,2 points

Finally as Butch missed 4 jumps, Butch should be awarded with 9,2 points

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the sum of three number is 202, the second is three more than the first number, the third number is three times the second numbe
sertanlavr [38]

Answer:

x = 38

y = 41

z = 123

Step-by-step explanation:

x + y + z = =202

y = x + 3

z = 3y = 3(x + 3) = 3x + 9

<u>x</u> + <u>y</u> + <u>z</u> = <u>x</u> + <u>x + 3</u> + <u>3x + 9</u> = 5x + 12 = 202

5x + 12 = 202

5x = 190

x = 38

y = x + 3 = 41

z = 3y = 123

4 0
3 years ago
Since 1924, 4 out of 22 Winter Olympics have been held in the U.S. In simplest form, what fraction of the Winter Olympics from 1
Dafna11 [192]
The fraction of winter Olympics that hasn't been held in the U. S is 9/11
6 0
3 years ago
2. A supermarket display consists of boxes of cereal. The bottom row has 27 boxes. Each row has four fewer boxes than the row be
tresset_1 [31]

Answer:

Step-by-step explanation:

) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

            = 23 + (5) x -3

            = 23 + (-15)

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b) Sum = N/2[2F + (N - 1) x D]

            = 6/2[2*23 + (6 - 1) x -3]

             = 3  [46  +    (5) x -3 ]

             = 3  [46  +      -15 ]

             = 3  [ 31 ]

             = 93 - total number of boxes in the entire display.

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Answer:

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