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3 years ago

Helppp pls, I cant seem to place them..

Mathematics

1 answer:

aleksandrvk [35]3 years ago

3 0

Subtract 5x from both sides, 7x+2=-26, subtract 2 from both sides, 7x=-28, divide both sides by 7, x=-4

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Prove

Dennis_Churaev [7]

$\frac{ \sin(a) - \cos(a) + 1 }{ \sin(a) + \cos(a) - 1 } = \\$

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$\frac{ \sin(a) - \cos(a) + 1 }{ \sin(a) + \cos(a) - 1 } \times \frac{ \sin(a) + \cos(a) + 1}{ \sin(a) + \cos(a) + 1 } =$

$\frac{ {sin}^{2}(a) + 2 \sin(a) - {cos}^{2} (a) + 1 }{ {sin}^{2}(a) + 2 \sin(a) \cos(a) + {cos}^{2}(a) - 1 } =$

_____________________________________________

As you know :

${sin}^{2} (a) + {cos}^{2} (a) = 1$

_____________________________________________

$\frac{ {sin}^{2} (a) - {cos}^{2}(a) + 2 \sin(a) + 1}{ {sin}^{2} (a) + {cos}^{2}(a) - 1 + 2 \sin(a) \cos(a) } =$

$\frac{ {sin}^{2}(a) - (1 - {sin}^{2}(a)) + 2 \sin(a) + 1 }{1 - 1 + 2 \sin(a) \cos(a) } =$

$\frac{ {sin}^{2} (a) + {sin}^{2} (a) - 1 + 1 + 2 \sin(a) }{2 \sin(a) \cos(a) } =$

$\frac{2 {sin}^{2}(a) + 2 \sin(a) }{2 \sin(a) \cos(a) } =$

$\frac{2 \sin(a)( \sin(a) + 1) }{2 \sin(a)( \cos(a) \: ) } = \\$

$\frac{ \sin(a) + 1}{ \cos(a) } \\$

And we're done...

Take care ♡♡♡♡♡

6 0

2 years ago

Use your angle pair relationships to find the missing angles.

Anit [1.1K]

Answer: Angle 2 = 127 degrees, Angle7 = 127 degrees, Angle 8 = 53 degrees

Step-by-step explanation:

Angle 2 = 127 degrees because it is supplementary to 53 degrees.

Angle 7 = 127 degrees because it is alternate exterior to angle 2.

Angle 8= 53 degrees because it is supplementary to angle 7.

8 0

2 years ago

Help me out

andrew-mc [135]

It’s B
PEMDAS. Exponents first then divide then add

7 0

1 year ago

Read 2 more answers

36 is what percent of 100? A. 0.36% B. 2.78% C. 277.8% D. 36%

34kurt

Answer: it B. 2.78%

Step-by-step explanation: if it wrong sorry

4 0

3 years ago

Read 2 more answers

1. In right triangle ABC, altitude CD is drawn to hypotenuse AB. If DB = 3 and CD = 6, find AD.

Alex Ar [27]

Answer:

3√2

Step-by-step explanation:

Given the following;

DB = 3

CD = 6,

Required

find AD.

using the similarity property of a triangle

DB/AD = AD/CD

3/AD = AD/6

3*6 = AD²

18 = AD²

AD = √18

AD= √9*√2

AD = 3√2

Hence the measure of AD is 3√2

5 0

3 years ago