Question

What is the value of n so that the expression x2 11x n is a perfect square trinomial

Answer 1

Answer:

$n=\frac{121}{4}$

Step-by-step explanation:

Since we know that perfect square trinomial formula states that any trinomial of the form $ax^{2} +bx+c$ is said to a perfect square if it satisfies the condition $b^{2} =4ac$.

We are given an expression $x^{2} ?11x ?n$ and asked to find value of n for expression to be a perfect square trinomial .

Let us compare our expression with perfect square trinomial formula.

We can see that a=1, b=11 and c=n.  

Let us find value of n by substituting our given values in $b^{2} =4ac$.

$11^{2} =4*1*n$

$121 =4n$.

$n=\frac{121}{4}$

Therefore, $n=\frac{121}{4}$ will make the expression $x^{2} ?11x ?n$ a perfect square trinomial.