Answer:
5 shirts
Step-by-step explanation:
2 pairs of jeans $25.60
$112.40-$25.60=$86.80
if each pair of T-shirts cost $15.30
$15.30 times 5=$76.50
$86.80 - $76.50=$10.30
so John bought 5 shirts however he got some many left $10.30
-- The filler pipe can fill 1/6 of the pool every hour.
-- The drainer pipe can drain 1/10 of the pool every hour.
-- When they're filling and draining at the same time, the filler pipe
will win eventually, because it finishes more of the pool in an hour
than what the drain pipe can finish in an hour.
-- When they're filling and draining at the same time, then every hour,
1/6 of the pool fills and 1/10 of it empties. The difference is (1/6) - (1/10).
To do that subtraction, we need a common denominator.
The smallest denominator that works is 30.
1/6 = 5/30
1/10 = 3/30 .
So in every hour, 5/30 of the pool fills, and 3/30 of the pool empties.
The result of both at the same time is that 2/30 = 1/15 fills each hour.
If nobody notices what's going on and closes the drain pipe, it will take
<em><u>15 hours</u></em> to fill the pool.
If the drain pipe had <em><u>not</u></em> been open, the filler pipe alone could have filled
the pool <em><u>2-1/2 times</u></em> in that same 15 hours. With both pipes open,
1-1/2 pool's worth of water went straight down the drain during that time,
and it was wasted.
I would say that the school should take the cost of 1-1/2 poolsworth out
of Ms. Charles' pay at the rate of $5 a week. I would, but that would
guarantee her more job security than she deserves after pulling a stunt
like that.
I hope this did not take place in California.
Answer:
x = 13/8
Step-by-step explanation:
sqrt(8x-4) +8 = 11
Subtract 8 from each side
sqrt(8x-4) +8-8 = 11-8
sqrt(8x-4) =3
Square each side
(sqrt(8x-4))^2 =3^2
8x-4 = 9
Add 4 to each side
8x-4+4 = 9+4
8x = 13
Divide by 8
8x/8 = 13/8
x = 13/8
Answer:
A) 
Step-by-step explanation:
*
** From what the problem said, we know that we selected the correct equation.
I am joyous to assist you anytime.
Explanation:
This can be explained by thinking numbers on the number line as:
Lets take we have to multiply a positive number (say, 2) with a negative number say (-3)
<u>2×(-3)</u>
Suppose someone is standing at 0 on the number line and to go to cover -3 , the person moves 3 units in the left hand side. Since, we have to compute for 2×(-3), The person has to cover the same distance twice. At last, he will be standing at -6, which is a negative number.
A image is shown below to represent the same.
<u>Thus, a positive times a negative is a negative number.</u>
