To solve this problem you must apply the proccedure shown below:
1. By definition, the rate of change of a linear function is the slope of the line and it is constant. Based on this, you must find the slope of the given function.
2. You have the equation of the line has the following form:

Where
is the slope and
is the y-intercept.
3. Then, you have that the slope of the function
is:

Therefore, the answer is: 
It should be 105 because it’s equal
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
5:03 because you take 8:11-3:48 so then you get 5:03
Answer:
One real root
Step-by-step explanation:
By the fundamental theorem of algebra, an nth degree polynomial has n-possible real roots.
If there are complex roots, then the the complex roots come in pairs.
Therefore the number of possible real roots of
are 3 real roots with no complex pairs or 1 real root with a complex pair.
By Descartes rule of signs, there is only one change of sign in the polynomial (+ to -).
Hence there is only one positive real root.

There is change is sign two times but we can not have even number of real roots for this polynomial
Therefore there is only real root.