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Elis [28]
4 years ago
11

The sum of the squares of two consecutive positive even integers is 100. find the two integers

Mathematics
1 answer:
liraira [26]4 years ago
3 0
The integers are 6 and 8
6^2= 36
8^2=64
36+64=100
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What is the rate of change for the linear function f(x)=-2x-5 over any interval?
Dmitry [639]

To solve this problem you must apply the proccedure shown below:

1. By definition, the rate of change of a linear function is the slope of the line and it is constant. Based on this, you must find the slope of the given function.

2. You have the equation of the line has the following form:

y=mx+b

Where mis the slope and b is the y-intercept.

3. Then, you have that the slope of the function f(x)=-2x-5 is:

m=-2

Therefore, the answer is: -2

7 0
4 years ago
Please answer this correctly
ehidna [41]
It should be 105 because it’s equal
7 0
3 years ago
A local chicken farmer is constructing a set of eight pens to cage his chickens as shown in the diagram below. He has decided to
Vilka [71]
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²

Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.

A'(x)=3000-18X

Set derivative equal to 0

0=3000-18X
166.6666666=X

Now test the intervals

(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -

Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5

Answer:
X= 166.6666666666
Y=5

Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
6 0
3 years ago
What is the elapse time for start time. 3:48 pm to end time : 8:11 pm?
Natalka [10]
5:03 because you take 8:11-3:48 so then you get 5:03
5 0
3 years ago
How many real roots would f(x)=<br> x^3+2x^2+2x-5 have
goldfiish [28.3K]

Answer:

One real root

Step-by-step explanation:

By the fundamental theorem of algebra, an nth degree polynomial has n-possible real roots.

If there are complex roots, then the the complex roots come in pairs.

Therefore the number of possible real roots of f(x)=x^3+2x^2+2x-5 are 3 real roots with no complex pairs or 1 real root with a complex pair.

By Descartes rule of signs, there is only one change of sign in the polynomial (+ to -).

Hence there is only one positive real root.

f(-x)=-x^3+2x^2-2x-5

There is change is sign two times but we can not have even number of real roots for this polynomial

Therefore there is only real root.

7 0
4 years ago
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