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anzhelika [568]
2 years ago
6

Please help. All answers or none, images attached.

Mathematics
2 answers:
TEA [102]2 years ago
7 0

slope=rise/run from left to right

rise=-3 becase goes down 3

run=4 because goes 4 units

slope=-3/4


boxes filled per minute is boxes/minute

pick a point, 3 boxes and 4 minutes, so that is 3/4 or 0.75 boxes per minute

anwers are 3 boxes every 4 minutes and 0.75 boxes per minute


that will be the one that passes through the point when time=1 minute, laps=3

looks like line b


slope=rise/run=(5000-3500)/(2-5)=-500

it drops 500m every minute

1st option

mixer [17]2 years ago
6 0

The line goes down 3 over to the right 4

-3/4

Choice B

The slope is -500.  The bird  descends......

3 boxes are filled every 4 minutes

.75 boxes  are filled per minute


3 laps per minute is line B

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1. (5pt) In a recent New York City marathon, 25,221 men finished and 253 dropped out. Also,
gladu [14]

Answer:

(a) Explained below.

(b) The 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

Step-by-step explanation:

The information provided is:

n (Men who finished the marathon) = 25,221

n (Women who finished the marathon) = 12,883

Compute the proportion of men and women who finished the marathon as follows:

\hat p_{1}=\frac{25221}{25221 +253}=0.99\\\\\hat p_{2}=\frac{12883 }{12883+163}=0.988

The combined proportion is:

\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}\\\\=\frac{25221+12883}{38520}\\\\=0.989

(a)

The hypothesis is:

<em>H</em>₀: The rate of those who finish the marathon is the same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ = 0.

<em>Hₐ</em>: The rate of those who finish the marathon is not same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ ≠ 0.

Compute the test statistic as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)\cdot [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.99-0.988}{\sqrt{0.989(1-0.989)\times[\frac{1}{25474}+\frac{1}{13046}]}}\\\\=1.78

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z>1.78)\\\\=2\times 0.03754\\\\=0.07508\\\\\approx 0.075

The <em>p</em>-value of the test is more than the significance level. The null hypothesis was failed to be rejected.

Thus, concluding that the rate of those who finish is the same for men and women.

(b)

Compute the 99% confidence interval for the difference between proportions as follows:

The critical value of <em>z</em> for 99% confidence level is 2.58.

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.99-0.988)\pm 2.58\times\sqrt{\frac{0.99(1-0.99)}{25474}+\frac{0.988(1-0.988)}{13046}}\\\\=0.002\pm 0.00294\\\\=(-0.00094, 0.00494)\\\\

Thu, the 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

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