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AnnyKZ [126]
3 years ago
13

Use this data for question #14. The results for a survey of 120 students who were selected randomly are listed below:

Mathematics
1 answer:
forsale [732]3 years ago
8 0
A i think it makes the most sense
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Proof by contadiction.

Let assume there exist such positive integers a and b whose sum is a prime number p, that their greatest common divisor is greater than 1.

a,b\in\mathbb{Z^+}\\d=\text{gcd}(a,b)>1\\\\a=de\\b=df\\e,f\in\mathbb{Z^+}\\\\a+b=p\\de+df=p\\d(e+f)=p\\

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Vikentia [17]
0.123\\\\digit\ in\ the\ tenths\ place\ is\ \boxed1

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<em>If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).</em>

0.\underline{1}23\approx\boxed{0.1}

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not a triangle because 8,12,14 does not =180

Step-by-step explanation:

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