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kari74 [83]
3 years ago
6

3 thousands 2 hundreds 15 tens 2 ones

Mathematics
2 answers:
baherus [9]3 years ago
7 0
3,352 is the answear.
Leona [35]3 years ago
6 0
32,153
 good luck hope this help need more help just send me a message 
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Write and simplify the integral that gives the arc length of the following curve on the given interval b. If necessary, use tech
LiRa [457]

Answer:

L = 4.103

Step-by-step explanation:

we have length of curve

L = \int\limits^b_a {\sqrt{(f'(x))²+1} } \, dx

where f(x) = d/dx(3*in(x)) = 3/x

substituting for f(x), we have L = \int\limits^5_2 {\sqrt{(3/x)²+1} } \, dx

(since the limit is 2≤ x ≤5)

solving,  L = \int\limits^5_2 {\sqrt{9/x²+1} } \, dx

Simplifying this integral, we have

L = 4.10321

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ser-zykov [4K]

Hello User!

Correction "Math"

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A retailer buys a radio from the wholesaler for $75.00. He then marks up the price by 1/3 and sells it at a discount of 20 %. Wh
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3 years ago
4 (j+17) -1 is greater than or equal to 19
Mars2501 [29]

4(j+17)-1\geq19\qquad\text{use distributive property}\\\\4j+68-1\geq19\\\\4j+67\geq19\qquad\text{subtract 67 from both sides}\\\\4j\geq-48\qquad\text{divide both sides by 4}\\\\j\geq-12

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6+b/b is an integer number. find all possible integer values of b​
Andrei [34K]

Step-by-step explanation:

(6+b)/b = x (= an integer number)

6 + b = bx (= still an integer number)

6 = bx - b = b(x - 1) (= still an integer number)

b = 6/(x - 1) (= still an integer number)

now for b to be integer, (x-1) must be a factor of 6 (6 must be divisible by x-1 with 0 remainder).

and integer includes negative numbers too.

the factors of 6 are therefore

1, 2, 3, 6, -1, -2, -3, -6

so, b can be 6/±1 = ±6

b can be 6/±2 = ±3

b can be 6/±3 = ±2

b can be 6/±6 = ±1

so, all possible values for b are also the listed factors of 6 :

-6, -3, -2, -1, 1, 2, 3, 6

5 0
2 years ago
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