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3 years ago

Help please! 10 points for this question

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Bottom left. Because of th eminus sign, the v curve is "upside-down" and because of the +1, its function value peak is at 1

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In factored form please help

Brilliant_brown [7]

Answer:

3rd option

Step-by-step explanation:

$\frac{3x^2-3}{x^2-5x+4}$ ( factorise numerator and denominator )

3x² - 3 ← factor out 3 from each term

= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

x² - 1

= x² - 1²

= (x - 1)(x + 1) , then

3x² - 3 = 3²(x - 1)(x + 1) ← in factored form

--------------------------------

x² - 5x + 4

consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

x² - 5x + 4 = (x - 1)(x - 4)

then

$\frac{3x^2-3}{x^2-5x+4}$ = $\frac{3(x-1)(x+1)}{(x-1)(x-4)}$ ← in factored form

3 0

2 years ago

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

zaharov [31]

After 6 years the investment is $5555.88

Step-by-step explanation:

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

The formula used to find future value is:

$A(t)=P(1+\frac{r}{n})^{nt}$

where A(t) = Accumulated amount

P = Principal Amount

r = annual rate

t= time

n= compounding periods per year

We are given:

P = $3600

r = 7.5 %

t = 6

n = 1

Putting values in formula:

$A(t)=P(1+\frac{r}{n})^{nt}\\A(t)=3600(1+\frac{0.075}{1})^{6*1}\\A(t)=3600(\frac{1.075}{1})^6\\A(t)=3600(1.075)^6\\A(t)=3600(1.543)\\A(t)=5555.88$

So, After 6 years the investment is $5555.88

Keywords: Compound Interest formula

Learn more about Compound Interest formula at:

#learnwithBrainly

8 0

3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago

-45+(-30)-90 the answer of that mathematics sum

Klio2033 [76]

The answer of
-45+(-30)-90= -165

Hope this helps <3

6 0

3 years ago

Read 2 more answers

Select "ALL" statements that correctly describe the graph!!

larisa86 [58]

Answer:

The slope is 1/2
The equation that represents this function is x -2y = 2

Step-by-step explanation:

Intercepts

The table shows the x-intercept to be (2, 0), and the y-intercept to be (0, -1). These are not matched by any of the answer choices.

Slope

The slope is ...

slope = (change in y)/(change in x) = (0 -(-1))/(2 -0) = 1/2

Equation

You can choose the equation by seeing if it works for a couple of points. You know the last equation is incorrect, because that slope-intercept form has the y-intercept as +1, not -1.

6 0

3 years ago