(3^0-(3^2)^3)/9^3
3^0=1
3^2=(3*3)=9->9^3=(9*9*9)=729
1-729=-728
9^3=(9*9*9)=729
-728/729
The required value is the angle theta and the value of the cosine of the angle is 0.9659
Given the expression of sine of an angle expressed as;

For us to get the cosine of the angle, we need to get the value of theta first as shown:

Next is to get the value of cos theta

The required value is the angle theta and the value of the cosine of the angle is 0.9659
Learn more here: brainly.com/question/13729598
Answer:
The product is 15. The answer is positive.
Step-by-step explanation:
The product of two numbers is the two numbers multiplied together. When two positive numbers are multiplied, the answer would be positive.
3 × 5 = 15
6. I think it's b but I could be wrong hope I helped.