Answer:
8 π or
25.13 unit^3 to the nearest hundredth.
Step-by-step explanation:
(A)
The height of the shell is (2 + x - x^2) and the radius is (2 - x).
V = 2π ∫(2 - x)(x + 2 - x^2) dx between the limits x = 0 and x = 2.
= 2π ∫ (2x + 4 - 2x^2 - x^2 - 2x + x^3) dx
= 2π ∫ (x^3 - 3x^2 + 4 ) dx
= 2π [ x^4/4 - x^3 + 4x ] between x = 0 and x = 2
= 2 π [4 - 8 + 8 )
= 2 π * 4
= 8π
= 25.13 unit^3 to the nearest hundredth.
Answer:
Step-by-step explanation:
Answer: x = 55/2
Step-by-step explanation: (x)(2) (-3)(2) = 49 2x-6+6 = 49+6 2x/2 = 55/2 x = 55/2
I know that my answer isn't a choice for one of the values of x but that's the result that I got when I solved (x–3)2 = 49.
Answer:
Below.
Step-by-step explanation:
To find the number of students in each grade you multiply the marks by the frequency density. The number of students is given by the area under the rectangles.
So to find the number of students with grade U (< 160) it is:
120 * 0.2 + 40*0.5
= 24 + 20
= 44.
The number for Grade E
= (200 - 160) * 0.5
= 40 * 0.5
= 20.
The others can be found in the same way.
