<h2>Answer: y = - x + 1
</h2>
<h3>Step-by-step explanation:
</h3>
For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:
The question gives us two points, (-3, 4) and (2, -1), from which we can find the slope and later the equation of the line.
<u>Finding the Slope</u>
The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= (4 - (- 1)) ÷ ((-3) - 2)
= - 1
<u>Finding the Equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - (-1) = - 1 (x - 2)
y + 1 = - (x - 2)
we could also transform this into the slope-intercept form ( y = mx + c) by making y the subject of the equation:
since y + 1 = - (x - 2)
∴ y = - x + 1
<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>
x=4 would be a vertical line
perimeter = Answer:
Step-by-step explanation:
5. Perimeter of semi circle = r(pi+2)
Given diameter=17m; r=17/2
Perimeter = (17/2)(pi+2)
6. Given diameter = 10.5
Perimeter = (10.5/2)(pi+2)
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
