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2 years ago

What are the coordinates of the vertex of the parabola described by the equation below? y=7(x+5)^2-4

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

4 0

Answer:

$y= 7(x+5)^2 -4$

The vertex form for a parabola is given by this expression:

$y = a(x-h)^2 +k$

By direct comparison we see that for this case:

$a = 7, h = -5 and k=-4$

And we know from the general expression that the vertex is:

$V= (h,k)$

So then the vertex for this case is:

$V= (-5,-4)$

Step-by-step explanation:

For this case we have the following function:

$y= 7(x+5)^2 -4$

And we need to take in count that the vertex form for a parabola is given by this expression:

$y = a(x-h)^2 +k$

By direct comparison we see that for this case:

$a = 7, h = -5 and k=-4$

And we know from the general expression that the vertex is:

$V= (h,k)$

So then the vertex for this case is:

$V= (-5,-4)$

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f(x=k) = -2k+1. you just replace the x with k.
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