The volume of the pipe is about 282.6 cubic feet.
First, we need to find the area of each circular cross section and subtract them to find the width of the pipe. The area of a circle is pi(r^2).
pi(3^2) - pi(2^2)
28.26 - 12.56 = 15.7
The width of the pipe is 15.7. Now, multiply that by 18 to find the volume.
15.7 x 18 = 282.6
Answer
theres nothing there
Step-by-step explanation:
You prob forgot to provide one
Answer:
the position of a particle moving at a coordinate say(y) will satisfy the given conditions t=0 (say) if y=2sint-cost
Step-by-step explanation:
Clearly by the above we can see that if y=2sint-cost at t=0, then y=-1 because at t=0 sint vanishes and leaves us with only cost and at t=0 cos0=1
Subtract the numbers. 71.45 - 70.24 = 1.21
==> Answer B
The circumference of the base is 40 cm, and this equals 2*pi*r. The radius, r, is found as follows:
40 cm
r = ------------ = 6.369 cm. The area of the base, A = pi*r^2, = 3.14*40.570
2(3.14)
The volume here is V = (1/3)(area of base)*(height)
= (1/3)(127.45)(9) cm^3 = 382.36 cm^3 (answer)
