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Setler [38]
3 years ago
15

What is the inequality shown

Mathematics
2 answers:
iogann1982 [59]3 years ago
6 0

Answer:

-4>x  and 5≤=x

Step-by-step explanation:

Hope this helps!!!

slavikrds [6]3 years ago
3 0
( -4 < x ≤ 5 ) This is the answer.
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Can you plz help me I don’t get it
levacccp [35]

35 feet.

\frac{mailbox height}{mailbox shadow}  

=

\frac{pinetree height}{pinetree shadow}

\frac{3}{4.8} = \frac{h}{56}

1.8<em>h</em> = 3 x 56

4.8<em>h</em> = 168

<em />

<em>h</em> = 35 feet.

5 0
3 years ago
Read 2 more answers
28 -4a = 3a -14+2a<br> ------
Greeley [361]
24+14 = 3a + 4a +2a
38 = 9a
——————————
Hope it is helpful.
6 0
3 years ago
Read 2 more answers
● For the polygon you are assigned, assume the radius is 1 unit . Round all answers to the nearest hundredth , if necessary.
lorasvet [3.4K]

9514 1404 393

Answer:

  1) 135°

  2) 0.77 units

  3) 0.92 units

  4) 6.12 units

  5) 2.83 square units

Step-by-step explanation:

1) The exterior angle at any vertex is 360°/n, where n is the number of sides. For the octagon, the exterior angle is 360°/8 = 45°. The interior angle will be the supplement of this: 180° -45° = 135°.

The measure of each interior angle is 135°.

__

2) Each sector of the octagon is an isosceles triangle with a central angle of 45° (also 360°/8). Since the radius is 1 unit, the length of one side is twice the sine of half the central angle.

  s = 2·sin(45°/2) ≈ 0.765367

The length of one side is about 0.77 units.

__

3) Similarly, the apothem is the cosine of half the central angle:

  a = cos(45°/2) ≈ 0.923880

The apothem is about 0.92 units.

__

4) For an octagon, the perimeter is 8 times the length of one side.

  P = 8s = 8(0.765367) ≈ 6.12293

The perimeter is about 6.12 units.

__

5) The area of one sector (isosceles triangle) is given by the formula ...

  A = (1/2)bh

  A = 1/2sa ≈ 1/2(0.765367)(0.923880) ≈ 0.353553

Then the area of the octagon is 8 times this:

  A = 8(sector area) = 8(0.353553) ≈ 2.82843

The octagon area is about 2.83 square units.

3 0
3 years ago
WILL MARK YOU BRAINLIEST, PLEASE HELP!!!
lutik1710 [3]

Given:ABCD is a rhombus.

To prove:DE congruent to BE.

In rombus, we know opposite angle are equal.

so, angle DCB = angle BAD

SINCE, ANGLE DCB= BAD

SO, In triangle DCA

angle DCA=angle DAC

similarly, In triangle ABC

angle BAC=angle BCA

since angle BCD=angle BAD

Therefore, angle DAC =angle CAB

so, opposite sides of equal angle are always equal.

so,sides DC=BC

Now, In triangle DEC and in triangle BEC

1. .DC=BC (from above)............(S)

2ANGLE CED=ANGLE CEB (DC=BC)....(A)

3.CE=CE (common sides)(S)

Therefore,DE is congruent to BE (from S.A.S axiom)

7 0
3 years ago
6. 150 is 75% of what number?
lora16 [44]

Answer: 8.2

Step-by-step explanation: So the way i do it is first i see that 6.15 is 75% of a number, and i know that 75% is 3/4. so i start by divided 6.15 by 3, and getting 2.05. i then times it by 4, making it 4/4. Therefore, getting 8.2

4 0
3 years ago
Read 2 more answers
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