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3 years ago

What is -3/8 divided by 7/12

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

When dividing fractions, multiply by the reciprocal:

-3/8 / 7/12
= -3/8 x 12/7 **reduce
= -3/2 x 3/7 **multiply numerators and denominators
= -9/14

Answer is the third option.

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Find the area of the parallelogram, 22mm 11mm. Please help im stu-pid

r-ruslan [8.4K]

The total area of the parallelogram is 242

Step by step:

A = b h = 22 x 11 = 242

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3 years ago

4 teammates share 5 granola bars equally. Draw to show how much each person gets. Shade the amount that one person gets

VLD [36.1K]

Answer:

This is hard to draw. on here....

But here goes:

Teammate 1:

{====} {=

Teammate 2:

{====} =

Teammate 3:

{====} =

Teammate 4:

{====} =}

So each teammate gets 1.25 or 1 1/4 of a granola bar

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3 years ago

Which of the following is true for the rational function f(x) = x-16/x-4 ?

Ratling [72]

<span>First of all, F is true because (16 - 16)/(16 - 4) = 0. It just means when you plug in that number (16) you'll get 0. This will NOT happen for 4 because the 0 is in the denominator.

Look what happens if you have x = 4. This gives you 12/0, which is undefined. For some graphs, this is a hole, but let's look closer.

What happens if you have x = 3.9? You'll have 12.1/0.1. 3.9999? 12.0001/0.0001. The closer you get to 4, the closer you'll get to y = infinity.

But what if you have 4.1? 11.9/-0.1. You'll get the same results, but NEGATIVE infinity. So it is NOT a hole in the graph.

If you draw it out, you'll see that there is a vertical asymptote at x = 4.

B and F are true.

As for horizontal asymptotes, look at it like this: y = 16-16/16 - 4 means y = 0. There is no asymptote here. Try subbing in 1 = (x -16)/(x - 4).
Multiply by x - 4 on both sides
x - 4 = x - 16
There is no solution here; there will be an asymptote, so D is also true.

B, D, and F are true. ,"yahoo answers"//////////////////if i get busted at least i put down my main source (you know what I'm saying)</span>

5 0

3 years ago

Read 2 more answers

A grocery store employs 15 cashiers, 25 stock clerks, and 10 delivery personnel. Among them, 10 cashiers, 10 stock clerks, and 5

boyakko [2]

Answer:

0.5 or 50%

Step-by-step explanation:

The number of total employees is:

$T=15+25+10 =50\ Employees$

The number of married employees is:

$M=10+10+5 =25\ Employees$

The probability that a randomly selected employee is not married is given by:

$P=1-\frac{M}{T}\\P=1-\frac{25}{50}\\P=0.5\ or\ 50\%$

The probability is 0.5 or 50%.

7 0

3 years ago

8. Based on the multiplication rule for independent events, what is the probability of getting an airplane in both boxes? Explai

Furkat [3]

Answer:

$P(A and B ) = \frac{1}{4}* \frac{1}{4}=\frac{1}{16}$

Step-by-step explanation:

We assume the following problem: "Consider the following ways students might create their lists using the notation:

B for block, W for watch, R for ring, and A for airplane. The first letter represents the toy found in the first box, and the second letter represents the toy found in the second box. The first column represents getting the block in the first box, followed by each one of the other toys. The second column represents getting the watch in the first box, followed by each one of the other toys. The third column is developed with the ring in the first box, and the fourth column is developed with the airplane in the first box"

And the possible outcomes are:

BB WB RB AB

BW WW RW AW

BR WR RR AR

BA WA RA AA

As we can see we have 16 possibilities.

For this case if we use the independence of events we have the following rule. If A and B are independent events then:

$P(A and B) = P(A) *P(B)$

Let A = Select an airplane from the total of 4 for the first box

B= Select an airplane from the total of 4 for the second box

For this case probability of getting an airplane selected in the first box is 1 out of 4 since we have just one outcome possible and 4 possible.

$P(A) = \frac{1}{4}$

And the probability of getting an airplane selected in the second box is also 1/4 since for the first box selected we have the same number of optiosn for the second box , 4.

$P(B) = \frac{1}{4}$

So then we have this:

$P(A and B ) = \frac{1}{4} \frac{1}{4}=\frac{1}{16}$

5 0

4 years ago