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Musya8 [376]
3 years ago
15

-4(-6 + 2) = A)-16 B)-32 C)-8 D)16

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0

Answer: A)-16

Step-by-step explanation:

Elenna [48]3 years ago
4 0

Step-by-step explanation:

- 4( - 6 + 2)

- 4( - 4) =  + 16

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Is this table proportional or non proportional?
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The table lists three points on the graph of a proportional relationship.

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4 years ago
If 15 apricots cost R5.60, how many apricots will R10.08 cost
balandron [24]

Hey!

Answer:

R5.60=15 apricots

R10.08=15÷5.60×10.08

=27 apricots {ans}

3 0
3 years ago
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Show all work to solve the equation for x. If a solution is extraneous, be sure to identify it. Square root of the quantity x +
creativ13 [48]

Answer:

x = 2 is the solution of the given equation

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given equation

  \sqrt{x+6-4} = x

squaring on both sides , we get

(\sqrt{x+2})^{2} = x^{2}

⇒ x + 2 = x²

⇒x² - x -2 =0

<u><em>Step(ii)</em></u>:-

  Given x² - x -2 =0

⇒ x² - 2x + x - 2 =0

⇒ x ( x-2) + 1(x - 2) =0

⇒ (x + 1) ( x-2) =0

⇒ x = -1 and x =2

x = 2 is the solution of the given equation

<u><em>Verification</em></u>:-

\sqrt{x+6-4} = x

Put x= 2

\sqrt{2+6-4} = 2

\sqrt{4} = 2

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6 0
4 years ago
A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia
Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which <em>k</em> items can be selected from <em>n</em> different items without replacement and  irrespective of the order.

{n\choose k}=\frac{n!}{k!(n-k)!}

Permutation is a mathematical procedure to determine the number of arrangements of <em>k</em> items from <em>n</em> different items respective of the order of arrangement.

^{n}P_{k}=\frac{n!}{(n-k)!}

In this case we need to select two different cards from a pack of 52 cards.

  • Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{52\choose 2}=\frac{52!}{2!(52-2)!}

      =\frac{52\times 51\times 50!}{2!\times50!}\\=1326

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

  • Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

^{n}P_{k}=\frac{n!}{(n-k)!}

^{52}P_{2}=\frac{52!}{(52-2)!}

       =\frac{52\times 51\times 52!}{50!}

       =52\times 51\\=2652

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0
3 years ago
How many hours is from 8am to 12pm
Ipatiy [6.2K]
I think it's 4 hours
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3 years ago
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