since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

8 0

2 years ago

Can someone please solve them?

lina2011 [118]

Answer:

Step-by-step explanation:

8 0

2 years ago

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Melia put the $30 her Grandmother gave her for her tenth birthday into her piggy bank. Each week after

Vladimir [108]

This is a sequence because the points form a straight line. The expression is: t(n) = 30 + 2x, x is number of weeks. On her 18th birthday, that is 8 years after her 10th. that means 416 weeks have passed since her 10th birthday. Plug 416 into the equation to get: t(416) = 30 + 2(416) = $862. She will have $862 to Spend.

3 0

2 years ago

When 27 times x squared times z all over negative 3 times x squared times z to the fourth power is completely simplified, the ex

snow_lady [41]

Isolate z by itself:

$\frac{z}{z^4}$

To simplify variables with powers, subtract the smaller power from the bigger power:

$4 - 1 = 3$
$\frac{z}{z^4} = \frac{1}{z^3} = z^{-3}$

The exponent will be -3.

4 0

2 years ago

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