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2 years ago

In 3/4 pound of spice mix there is 5/6 cup of cinnamon how much cinnamon does spice mix contain per pound?

1 answer:

6 0

Let's use ratio and proportion or rates to solve thisIf there is 5/6 cup of cinnamon in a 3/4 pound of spice mix, how many are in a pound?5/6=3/4 ?=11/ (3/4)*5/6=11/9Therefore there are 11/9 cups of cinnamon in 1.1 pounds of spice mix

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Is finding 9/10-1/2 the same as finding 9/10-1/4-1/4?explain.

zavuch27 [327]

Yes it is the same. 1/4 +1/4 = 1/2. so 9/10-1/2=9/10-1/2

5 0

3 years ago

Find the value of y round your answer to the nearest tenth cos y y=8/13

Iteru [2.4K]

8/13 = 0.6153

y = cos-1(0.6153)

y = 52.0

I'm not totally sure if this is what you mean or if this is.

y = cos(8/13) = 0.9999 which to the nearest tenth is 1.0

7 0

3 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Find the height of a triangle that has an area of 54 cm2 with the width 3 cm less than its height.

iren2701 [21]

The height of a triangle is 9 cm

<h3>What is Triangle?</h3>

A polygon with three edges and three vertices is called a triangle. It is one of the fundamental geometric shapes. Triangle ABC is the display style for a triangle with vertices A, B, and C.
In Euclidean geometry, any three points that are not collinear produce a singular triangle and a singular plane (i.e. a two-dimensional Euclidean space).
In other words, every triangle is contained in a plane, and there is only one plane that contains that triangle.
All triangles are enclosed in a single plane if all of the geometry is the Euclidean plane, however, this is no longer true in higher-dimensional Euclidean spaces.
Except when otherwise specified, this article discusses triangles in Euclidean geometry, namely the Euclidean plane.

given that

let the height of the triangle be x

then the width is x-3

Area = $\frac{height \times length}{2}$