Equivalent equations are equations that have the same value
The equation in logarithmic form is ![t = \frac{\log(9)}{2}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%289%29%7D%7B2%7D)
<h3>How to rewrite the equation</h3>
The expression is given as:
![10^{2t} = 9](https://tex.z-dn.net/?f=10%5E%7B2t%7D%20%3D%209)
Take the logarithm of both sides
![\log(10^{2t}) = \log(9)](https://tex.z-dn.net/?f=%5Clog%2810%5E%7B2t%7D%29%20%3D%20%5Clog%289%29)
Apply the power rule of logarithm
![2t\log(10) = \log(9)](https://tex.z-dn.net/?f=2t%5Clog%2810%29%20%3D%20%5Clog%289%29)
Divide both sides by log(10)
![2t = \frac{\log(9)}{\log(10)}](https://tex.z-dn.net/?f=2t%20%3D%20%5Cfrac%7B%5Clog%289%29%7D%7B%5Clog%2810%29%7D)
Apply change of base rule
![2t = \log_{10}(9)](https://tex.z-dn.net/?f=2t%20%3D%20%5Clog_%7B10%7D%289%29)
Divide both sides by 2
![t = \frac{\log_{10}(9)}{2}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog_%7B10%7D%289%29%7D%7B2%7D)
Rewrite as:
![t = \frac{\log(9)}{2}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%289%29%7D%7B2%7D)
Hence, the equation in logarithmic form is ![t = \frac{\log(9)}{2}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%289%29%7D%7B2%7D)
Read more about logarithms at:
brainly.com/question/25710806
Answer:
x^4
Step-by-step explanation:
(x^(2/5))^10
x^(2/5*10)
x^(20/5)
x^4
The first one is right and the third one is right, but you need to switch the 15% and the 95%.
In #2, it's asking for the kids that <em>are not</em> Michael, so it'd be 18/19. Which is then rounded to roughly 95%.
#4 asks for 6/40 = 15%
Answer:
B. -4
Step-by-step explanation:
To find the slope you can count the difference between the 2 points. Slope is rise over run. This means that slope is equal to change in y/ change in x. In this case, the 2 y-values are 8 and -4. This is a decrease of 12, aka -12. Then, the 2 x-values are -1 and 2. This is an increase of 3. Therefore the slope is -12/3. When simplified this equals -4.
Additionally, there is a slope formula,
. If you plug in the values, you will get the same answer as the technique above.
C is the answer to this question. I hope this helps.