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AnnZ [28]
2 years ago
6

Which two cell parts are most likely found in both types of cell? Ocell wall and cell membrane O lysosome and vacuole O vacuole

and centriole O lysosome and chloroplast​
Biology
1 answer:
atroni [7]2 years ago
4 0

Answer:

The correct answer is - lysosome and vacuole.

Explanation:

In the cells of animals and plants, there are many similarities and some differences as well. These similarities and differences include the organelle they both have common or specific to a particular cell.

Lysosome and the vacuoles are two organelles found in both cells; plants, and animals. In plants, there is a central vacuole large in size whereas in the animal cells the numbers are much higher and size is smaller in size. Lysosomes are also present in both animals as well as the plant cell.

Thus, the correct answer is - lysosomes and vacuole.

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The correct answer would be gametes

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Sheena wants to measure the volume of a ball that is 24 cm across. How should she set up her equation?
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Given that Sheena's ball is a sphere, its volume can be obtained by using the formula: V_ball = (4/3)*pi*r^3, where, r is the radius of the sphere. Since the ball is 24 cm across, this means that the radius is half of the diameter which is equal to 12 cm. Thus, the volume of the ball is equal to 7238.2295 cm^2.
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3 0
2 years ago
How many grams of the compound in the figure above are required to make 1 liter of a 0.5 M solution? (Note: The atomic masses, i
Dafna1 [17]

Answer:

This question is incomplete as there is no figure in the question but the compound in the figure is Ethanoic acid (CH3COOH). Hence, we can calculate the mass.

The answer is: 30grams

Explanation:

According to the question, the volume of the compound (CH3COOH) is 1litre while the molar concentration is 0.5M

Molarity or Molar concentration is calculated using the formula:

M= n/V

Where; M= Molarity (M) = 0.5M

n= number of moles (mol)

V= Volume (V) = 1L

Hence, number of moles (n) = M × V

n = 0.5 × 1

n = 0.5 moles.

To calculate the mass in grams of CH3COOH, we say;

Number of moles (n) × molar mass (MM)

Since atomic mass for (C= 12, H= 1 and O=16)

Molar mass of CH3COOH:

= 12 + 1(3) + 12 + 16 + 16 + 1

Molar mass of CH3COOH = 60g/mol

Mass (in grams) of CH3COOH = 0.5 moles × 60g/mol

Mass = 30grams.

Therefore, 30grams of CH3COOH compound are required to make 1 liter of a 0.5 M solution.

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