5+7 = 12
60/12 = 5
5 x 5 = 25
5 x 7 = 35
<span>60 in the ratio of 5:7 = 25:35
hope it helps</span>
We are given
△ABC, m∠A=60° m∠C=45°, AB=8
Firstly, we will find all angles and sides
Calculation of angle B:
we know that sum of all angles is 180
m∠A+ m∠B+m∠C=180
we can plug values
60°+ m∠B+45°=180
m∠B=75°
Calculation of BC:
we can use law of sines
now, we can plug values
Calculation of AC:
now, we can plug values
Perimeter:
we can plug values
Area:
we can use formula
now, we can plug values
...............Answer
Answer:
y=4x-3
then add 3 to each side to get: y+3=4x.
Next, just divide both sides by 4 to get x = (y+3)\div4.
Following transformations on Triangle ABC will result in the Triangle A'B'C'
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)
In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)
First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'.
Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'.
The same way C is translated to C'.
Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
Answer:
x=14 and y=37
Step-by-step explanation:
9x+12+3x=180
12x=168
x= 14
4y-10+42=180
4y=148
y=37
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